You can find the second largest number in Python using the following steps:
- Define a list of numbers.
- Use the built-in
max()
function to find the maximum number in the list. - Remove the maximum number from the list using the
remove()
method. - Use the
max()
function again on the updated list to find the second largest number.
Here’s the code:
numbers = [10, 20, 30, 40, 50] max_number = max(numbers) numbers.remove(max_number) second_max_number = max(numbers) print(second_max_number)
Output:
40
In this example, the second largest number in the list is 40
.
Sorting the list and then print the second last number:
Sure! Here’s how you can sort a list in Python and print the second last number:
numbers = [10, 20, 30, 40, 50] numbers.sort() # Sort the list in ascending order second_last_number = numbers[-2] # Get the second last number print(second_last_number)
Output:
40
In this example, the second last number in the sorted list is 40
. Note that we used the negative index -2
to access the second last element of the list, since Python indices start at 0.
Removing the maximum element:
Sure! Here’s an example of how you can remove the maximum element from a list in Python:
numbers = [10, 20, 30, 40, 50] max_number = max(numbers) # Find the maximum number numbers.remove(max_number) # Remove the maximum number from the list print(numbers)
Output:
[10, 20, 30, 40]
In this example, we found the maximum number in the list using the max()
function, and then removed it from the list using the remove()
method. The resulting list is [10, 20, 30, 40]
, with the maximum element 50
removed.