You can find the second largest number in Python using the following steps:

- Define a list of numbers.
- Use the built-in
`max()`

function to find the maximum number in the list. - Remove the maximum number from the list using the
`remove()`

method. - Use the
`max()`

function again on the updated list to find the second largest number.

Here’s the code:

numbers = [10, 20, 30, 40, 50] max_number = max(numbers) numbers.remove(max_number) second_max_number = max(numbers) print(second_max_number)

Output:

40

In this example, the second largest number in the list is `40`

.

### Sorting the list and then print the second last number:

Sure! Here’s how you can sort a list in Python and print the second last number:

numbers = [10, 20, 30, 40, 50] numbers.sort() # Sort the list in ascending order second_last_number = numbers[-2] # Get the second last number print(second_last_number)

Output:

40

In this example, the second last number in the sorted list is `40`

. Note that we used the negative index `-2`

to access the second last element of the list, since Python indices start at 0.

### Removing the maximum element:

Sure! Here’s an example of how you can remove the maximum element from a list in Python:

numbers = [10, 20, 30, 40, 50] max_number = max(numbers) # Find the maximum number numbers.remove(max_number) # Remove the maximum number from the list print(numbers)

Output:

[10, 20, 30, 40]

In this example, we found the maximum number in the list using the `max()`

function, and then removed it from the list using the `remove()`

method. The resulting list is `[10, 20, 30, 40]`

, with the maximum element `50`

removed.